Solved A bag contains three red marbles, two green ones, one
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Solved A bag contains three red marbles, two green ones, one

A bag contains 3 white, 4 black, and 2 red marbles. Two marbles are drawn from the bag. If replacement is not allowed, what is the probability that the second marble drawn will be red? I disagree with the given answer $\frac29$. Can someone please point why my solution is wrong? P(Both Red) + P(Second is Red): P(Both Red) $=\frac{\binom22.. A bag contains 3 red marbles and 4 blue marbles. Two marbles are drawn at random without replacement. If the first marble drawn is blue, what is the probability the second marble is also blue? Select one: O a. 2/3 O b. 4/7 O C. 3/7 O d. 1/2


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The 1000 Marbles Resilient Minds

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A bag contains 1 blue, 2green,

A bag contains 1 blue, 2green, 3 yellow, and 3 red marbles, as shown. What’s is the probability

Two marbles are drawn at random and with replacement from a box containing $2$ red, $3$ green, and $4$ blue marbles. Let’s define the following events: A={two red marbles are drawn} B={ two green marbles are drawn} C={two blue marbles are drawn}. Let’s say i want to find the probability of A.. A bag contains 3 red marbles and 4 blue marbles. a marble is taken at random and replaced. Another marble is taken from the bag. Work out the probability that the two marbles taken from the bag are the same color. Total number of marbles in the bag is 3 + 4 = 7. The problem asks for the probability of (RR) or (BB).